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done on an object when a force of 1 N
displaces it by 1 m along the line of action of
the force.
Look at Eq. (10.1) carefully. What is the
work done when the force on the object is
zero? What would be the work done when
the displacement of the object is zero? Refer
to the conditions that are to be satisfied to
Fig. 10.4
say that work is done.
Consider a situation in which an object is
moving with a uniform velocity along a
Example 10.1 A force of 5 N is acting on
particular direction. Now a retarding force, F,
an object. The object is displaced
is applied in the opposite direction. That is,
through 2 m in the direction of the force
the angle between the two directions is 180º.
(Fig. 10.2). If the force acts on the object Let the object stop after a displacement s. In
all through the displacement, then work such a situation, the work done by the force,
done is 5 N × 2 m =10 N m or 10 J. F is taken as negative and denoted by the
minus sign. The work done by the force is
F × (–s) or (–F × s).
It is clear from the above discussion that
the work done by a force can be either positive
or negative. To understand this, let us do the
following activity:
Fig. 10.2
Activity _____________10.4
uestion
Q 1. A force of 7 N acts on an object. force exerted by you on the object. The
Lift an object up. Work is done by the
•
object moves upwards. The force you
The displacement is, say 8 m, in
exerted is in the direction of
the direction of the force
displacement. However, there is the
(Fig. 10.3). Let us take it that the
force acts on the object through
Which one of these forces is doing
the displacement. What is the • force of gravity acting on the object.
positive work?
work done in this case? • Which one is doing negative work?
• Give reasons.
Work done is negative when the force acts
opposite to the direction of displacement.
Work done is positive when the force is in the
Fig. 10.3
direction of displacement.
Example 10.2 A porter lifts a luggage of
Consider another situation in which the
15 kg from the ground and puts it on
force and the displacement are in the same
direction: a baby pulling a toy car parallel to his head 1.5 m above the ground.
the ground, as shown in Fig. 10.4. The baby Calculate the work done by him on the
has exerted a force in the direction of luggage.
displacement of the car. In this situation, the
Solution:
work done will be equal to the product of the
force and displacement. In such situations, Mass of luggage, m = 15 kg and
the work done by the force is taken as positive. displacement, s = 1.5 m.
WORK AND ENERGY 115
Rationalised 2023-24