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done on an object when a force of 1 N
                 displaces it by 1 m along the line of action of
                 the force.
                    Look at Eq. (10.1) carefully.  What is the
                 work done when the force on the object is
                 zero? What would be the work done when
                 the displacement of the object is zero? Refer
                 to the conditions that are to be satisfied to
                                                                                    Fig. 10.4
                 say that work is done.
                                                                     Consider a situation in which an object is
                                                                 moving with a uniform velocity along a
                  Example 10.1 A force of 5 N is acting on
                                                                 particular direction. Now a retarding force, F,
                     an object. The object is displaced
                                                                 is applied in the opposite direction. That is,
                     through 2 m in the direction of the force
                                                                 the angle between the two directions is 180º.
                     (Fig. 10.2). If the force acts on the object  Let the object stop after a displacement s. In
                     all through the displacement, then work     such a situation, the work done by the force,
                     done is 5 N × 2 m  =10 N m or 10 J.         F is taken as negative and denoted by the
                                                                 minus sign. The work done by the force is
                                                                 F × (–s) or (–F × s).
                                                                     It is clear from the above discussion that
                                                                 the work done by a force can be either positive
                                                                 or negative. To understand this, let us do the
                                                                 following activity:
                                    Fig. 10.2
                                                                    Activity _____________10.4
                      uestion
                Q       1. A force of 7 N acts on an object.             force exerted by you on the object.  The
                                                                         Lift an object up. Work is done by the
                                                                    •
                                                                         object moves upwards. The force you
                            The displacement is, say 8 m, in
                                                                         exerted is in the direction of
                            the direction of the force
                                                                         displacement. However, there is the
                            (Fig. 10.3).  Let us take it that the
                            force acts on the object through
                                                                         Which one of these forces is doing
                            the displacement. What is the           •    force of gravity acting on the object.
                                                                         positive work?
                            work done in this case?                 •    Which one is doing negative work?
                                                                    •    Give reasons.
                                                                     Work done is negative when the force acts
                                                                 opposite to the direction of displacement.
                                                                 Work done is positive when the force is in the
                                    Fig. 10.3
                                                                 direction of displacement.

                                                                   Example   10.2 A porter lifts a luggage of
                    Consider another situation in which the
                                                                      15 kg from the ground and puts it on
                 force and the displacement are in the same
                 direction:  a baby pulling a toy car parallel to     his head 1.5 m above the ground.
                 the ground, as shown in Fig. 10.4.  The baby         Calculate the work done by him on the
                 has exerted a force in the direction of              luggage.
                 displacement of the car. In this situation, the
                                                                   Solution:
                 work done will be equal to the product of the
                 force and displacement. In such situations,          Mass of luggage, m       = 15 kg and
                 the work done by the force is taken as positive.     displacement, s = 1.5 m.


                 WORK AND ENERGY                                                                       115





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