Page 190 - NCERT Science Class 10 English Medium
P. 190

Applying Ohm’s law to the electric lamp and conductor separately,
                    we get potential difference across the electric lamp,
                    V   = 20 Ω × 0.25 A
                      1
                        = 5 V;
                    and,
                    that across the conductor, V   =  4 Ω × 0.25 A
                                                 2
                                                      =  1 V.
                    Suppose that we like to replace the series combination of electric
                    lamp and conductor by a single and equivalent resistor. Its resistance
                    must be such that a potential difference of 6 V across the battery
                    terminals will cause a current of 0.25 A in the circuit. The resistance
                    R of this equivalent resistor would be
                    R   = V/I
                        = 6 V/ 0.25 A
                        = 24 Ω.
                    This is the total resistance of the series circuit; it is equal to the sum
                    of the two resistances.



                                     Q      U       E     S     T      I     O      N      S


                    1.   Draw a schematic diagram of a circuit consisting of a battery of three
                         cells of 2 V each, a 5 Ω resistor, an 8 Ω resistor, and a 12 Ω resistor, and
                         a plug key, all connected in series.
                    2.   Redraw the circuit of Question 1, putting in an ammeter to measure      ?
                         the current through the resistors and a voltmeter to measure the
                         potential difference across the 12 Ω resistor. What would be the readings
                         in the ammeter and the voltmeter?

                 11.6.2 Resistors in Parallel

                 Now, let us consider the arrangement of three resistors joined in parallel
                 with a combination of cells (or a battery), as shown in Fig.11.7.

                     Activity
                     Activity 11.611.6
                     Activity 11.6
                                 11.6
                     Activity
                     Activity 11.6
                   n Make a parallel combination, XY, of three
                      resistors having resistances R ,  R , and  R ,
                                                   1  2       3
                      respectively. Connect it with a battery, a
                      plug key and an ammeter, as shown in
                      Fig. 11.10. Also connect a voltmeter in
                      parallel with the combination of resistors.
                   n Plug the key and note the ammeter reading.
                      Let the current be I. Also take the voltmeter
                      reading. It gives the potential difference V,
                      across the combination. The potential
                      difference across each resistor is also V. This
                      can be checked by connecting the voltmeter
                      across each individual resistor (see
                                                                                   Figure 11.1011.10
                                                                                   Figure
                                                                                   Figure
                                                                                          11.10
                                                                                   Figure 11.10
                      Fig. 11.11).                                                 Figure 11.10
                 Electricity                                                                              185

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