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Activity 9.10
                     Activity 9.109.10
                     Activity 9.10
                                 9.10
                     Activity
                     Activity
                   n Fix a sheet of white paper on a drawing board using drawing pins.
                   n Place a rectangular glass slab over the sheet in the middle.
                   n Draw the outline of the slab with a pencil. Let us name the outline
                      as ABCD.
                   n Take four identical pins.
                   n Fix two pins, say E and F, vertically such that the line joining the
                      pins is inclined to the edge AB.
                   n Look for the images of the pins E and F through the opposite edge.
                      Fix two other pins, say G and H, such that these pins and the
                      images of E and F lie on a straight line.
                   n Remove the pins and the slab.
                   n Join the positions of tip of the pins E and F and produce the line
                      up to AB. Let EF meet AB at O.  Similarly, join the positions of tip
                      of the pins G and H and produce it up to the edge CD.   Let HG
                      meet CD at O′.
                   n Join O and O′.  Also produce EF up to P, as shown by a dotted line
                      in Fig. 9.10.

                    In this Activity, you will note, the light ray has changed its direction
                 at points O and O′. Note that both the points O and O′ lie on surfaces
                 separating two transparent media. Draw a perpendicular NN’ to AB at O
                 and another perpendicular MM′ to CD at O′. The light ray at point O has
                 entered from a rarer medium to a denser medium, that is, from air to
                 glass. Note that the light ray has bent towards
                 the normal. At O′, the light ray has entered
                 from glass to air, that is, from a denser
                 medium to a rarer medium.  The light here
                 has bent away from the normal. Compare the
                 angle of incidence with the angle of refraction
                 at both refracting surfaces AB and CD.
                    In Fig. 9.10, a ray EO is obliquely
                 incident on surface AB, called incident ray.
                 OO′  is the refracted ray and O′  H is the
                 emergent ray. You may observe that the
                 emergent ray is parallel to the direction of
                 the incident ray. Why does it happen so? The
                 extent of bending of the ray of light at the
                 opposite parallel faces AB (air-glass interface)
                 and CD (glass-air interface) of the rectangular
                 glass slab is equal and opposite. This is why
                 the ray emerges parallel to the incident ray.
                 However, the light ray is shifted sideward    Figure 9.109.10
                                                               Figure
                                                               Figure 9.10
                                                                       9.10
                                                               Figure
                                                               Figure 9.10
                 slightly. What happens when a light ray is    Refraction of light through a rectangular glass slab
                 incident normally to the interface of two
                 media? Try and find out.
                    Now you are familiar with the refraction of light. Refraction is due to
                 change in the speed of light as it enters from one transparent medium to
                 another.  Experiments show that refraction of light occurs according to
                 certain laws.


                 Light – Reflection and Refraction                                                        147


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