Page 149 - NCERT Science Class 10 English Medium
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Example 9.1
                                         A convex mirror used for rear-view on an automobile has a radius of
                                         curvature of 3.00 m. If a bus is located at 5.00 m from this mirror,
                                         find the position, nature and size of the image.

                                         Solution
                                         Radius of curvature, R = + 3.00 m;
                                         Object-distance,     u = – 5.00 m;
                                         Image-distance,      v = ?
                                         Height of the image, h′= ?

                                                                 3.00 m
                                         Focal length, f = R/2 = +       = + 1.50 m (as the principal focus of
                                                                    2
                                            a convex mirror is behind the mirror)
                                               1   1    1
                                         Since   +   =
                                               v   u    f

                                             1   1   1       1         1        1      1
                                         or,   =   −    = +        –         =     +
                                             v   f   u      1.50    ( 5.00)   1.50    5.00
                                                                    −
                                             5.00 1.50
                                                 +
                                            =
                                                7.50
                                             + 7.50
                                         v =        = + 1.15 m
                                              6.50
                                         The image is 1.15 m at the back of the mirror.

                                                            h  '   v      1.15 m
                                         Magnification, m =    = −   =  –
                                                             h     u      − 5.00 m
                                                           = + 0.23
                                         The image is virtual, erect and smaller in size by a factor of 0.23.


                                         Example 9.2
                                         An object, 4.0 cm in size, is placed at 25.0 cm in front of a concave
                                         mirror of focal length 15.0 cm. At what distance from the mirror
                                         should a screen be placed in order to obtain a sharp image? Find
                                         the nature and the size of the image.
                                         Solution
                                         Object-size, h =  + 4.0 cm;
                                         Object-distance, u = – 25.0 cm;
                                         Focal length, f = –15.0 cm;
                                         Image-distance,   v = ?
                                         Image-size, h′ = ?
                                         From Eq. (10.1):

                                          1   1   1
                                            +   =
                                          v   u   f
                                              1  1    1     1       1         1      1
                                         or,    =   −   =       −        = −      +
                                              v   f   u   − 15.0  − 25.0    15.0    25.0

               144                                                                                   Science


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